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change logic of when to show the call and share button. (#12385)

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Allow starting calls in rooms with only one person if one can add invite others with a call link.

Signed-off-by: Timo K <toger5@hotmail.de>
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Timo 2024-04-04 15:36:07 +02:00 • committed by GitHub
parent 307d737555
commit 015b9386e1
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2 changed files with 32 additions and 5 deletions
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10
src/hooks/room/useRoomCall.ts
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@ -189,6 +189,8 @@ export const useRoomCall = (
// We only want to prompt to pin the widget if it's not element call based.
const isECWidget = WidgetType.CALL.matches(widget?.type ?? "");
const promptPinWidget = !isECWidget && canPinWidget && !widgetPinned;
const userId = room.client.getUserId();
const canInviteToRoom = userId ? room.canInvite(userId) : false;
const state = useMemo((): State => {
if (activeCalls.find((call) => call.roomId != room.roomId)) {
return State.Ongoing;
@ -199,8 +201,9 @@ export const useRoomCall = (
if (hasLegacyCall) {
return State.Ongoing;
}
if (memberCount <= 1) {
const canCallAlone =
canInviteToRoom && (room.getJoinRule() === "public" || room.getJoinRule() === JoinRule.Knock);
if (!(memberCount > 1 || canCallAlone)) {
return State.NoOneHere;
}
@ -210,6 +213,7 @@ export const useRoomCall = (
return State.NoCall;
}, [
activeCalls,
canInviteToRoom,
hasGroupCall,
hasJitsiWidget,
hasLegacyCall,
@ -218,7 +222,7 @@ export const useRoomCall = (
mayEditWidgets,
memberCount,
promptPinWidget,
room.roomId,
room,
]);
const voiceCallClick = useCallback(